Mathematics · 2026
JEE Main · 5 April 2026, Shift 1 · Q18
The value of the integral ∫_0^∞ (log_e(x))/(x^2+4) d x is:
The value of the integral $\displaystyle \int_0^{\infty} \frac{\log _e(x)}{x^2+4} d x$ is:
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{\pi \log _e(2)}{4}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.