Mathematics · 2021
JEE Main · 25 July 2021, Shift 2 · Q73
The value of cot (π)/24 is:
The value of $\displaystyle \cot \frac{\pi}{24}$ is :
Official answer
(2)
$\displaystyle \sqrt{2}+\sqrt{3}+2+\sqrt{6}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.