Mathematics · 2020
JEE Main · 5 September 2020, Shift 2 · Q69
If L = sin^2((π)/16)- sin^2((π)/8) and M= cos^2((π)/16)- sin^2((π)/8), then:
If $\displaystyle \mathrm{L}=\sin ^2\left(\frac{\pi}{16}\right)-\sin ^2\left(\frac{\pi}{8}\right)$ and $\displaystyle M=\cos ^2\left(\frac{\pi}{16}\right)-\sin ^2\left(\frac{\pi}{8}\right)$, then :
Official answer
(3)
$\displaystyle M=\frac{1}{2 \sqrt{2}}+\frac{1}{2} \cos \frac{\pi}{8}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.