If the line x=y=z intersects the line x sin A+y sin B+z sin C-18=0=x sin 2 A+y sin 2 B+z sin 2 C-9, where A, B, C are the angles of a triangle A B C,…

If the line $\displaystyle x=y=z$ intersects the line $$x \sin A+y \sin B+z \sin C-18=0=x \sin 2 A+y \sin 2 B+z \sin 2 C-9, $$ where $\displaystyle A, B, C$ are the angles of a triangle $\displaystyle A B C$, then $\displaystyle 80\left(\sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2}\right)$ is equal to $\displaystyle \_\_\_\_$.