Mathematics · 2023
JEE Main · 10 April 2023, Shift 1 · Q19
96 cos (π)/33 cos (2 π)/33 cos (4 π)/33 cos (8 π)/33 cos (16 π)/33 is equal to
$\displaystyle 96 \cos \frac{\pi}{33} \cos \frac{2 \pi}{33} \cos \frac{4 \pi}{33} \cos \frac{8 \pi}{33} \cos \frac{16 \pi}{33}$ is equal to
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 3$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.