Mathematics · 2023
JEE Main · 8 April 2023, Shift 2 · Q19
The value of 36(4 cos^2 9^°-1)(4 cos^2 27^°-1)(4 cos^2 81^°-1)(4 cos^2 243^°-1) is
The value of $\displaystyle 36\left(4 \cos ^2 9^{\circ}-1\right)\left(4 \cos ^2 27^{\circ}-1\right)\left(4 \cos ^2 81^{\circ}-1\right)\left(4 \cos ^2 243^{\circ}-1\right)$ is
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 36$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.