Mathematics · 2025
JEE Main · 23 January 2025, Shift 1 · Q11
The value of ( sin 70^°)( cot 10^° cot 70^°-1) is
The value of $\displaystyle \left(\sin 70^{\circ}\right)\left(\cot 10^{\circ} \cot 70^{\circ}-1\right)$ is
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 1$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.