Mathematics · 2026
JEE Main · 4 April 2026, Shift 1 · Q23
If A =(sin 3^°)/(cos 9^°)+(sin 9^°)/(cos 27^°)+(sin 27^°)/(cos 81^°) and B = tan 81^°- tan 3^°, then B/A is equal to ____.
If $\displaystyle \mathrm{A}=\frac{\sin 3^{\circ}}{\cos 9^{\circ}}+\frac{\sin 9^{\circ}}{\cos 27^{\circ}}+\frac{\sin 27^{\circ}}{\cos 81^{\circ}}$ and $\displaystyle \mathrm{B}=\tan 81^{\circ}-\tan 3^{\circ}$, then $\displaystyle \frac{\mathrm{B}}{\mathrm{A}}$ is equal to
$\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
2
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.