Mathematics · 2021
JEE Main · 27 July 2021, Shift 1 · Q74
If sin θ+ cos θ=1/2, then 16( sin (2 θ)+ cos (4 θ)+ sin (6 θ)) is equal to:
If $\displaystyle \sin \theta+\cos \theta=\frac{1}{2}$, then $\displaystyle 16(\sin (2 \theta)+\cos (4 \theta)+\sin (6 \theta))$ is equal to :
Official answer
(2)
$\displaystyle -23$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.