Mathematics · 2021
JEE Main · 17 March 2021, Shift 1 · Q80
The sum of possible values of x for tan^-1(x+1)+ cot^-1(1/(x-1))= tan^-1(8/31) is:
The sum of possible values of $\displaystyle x$ for $\displaystyle \tan ^{-1}(x+1)+\cot ^{-1}\left(\frac{1}{x-1}\right)=\tan ^{-1}\left(\frac{8}{31}\right)$ is :
Official answer
(2)
$\displaystyle -\frac{32}{4}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.