Mathematics · 2021
JEE Main · 17 March 2021, Shift 1 · Q68
If cot^-1(α)= cot^-1 2+ cot^-1 8+ cot^-1 18+ cot^-1 32+….. upto 100 terms, then α is:
If $\displaystyle \cot ^{-1}(\alpha)=\cot ^{-1} 2+\cot ^{-1} 8+\cot ^{-1} 18+\cot ^{-1} 32+\ldots .$. upto $\displaystyle 100$ terms, then $\displaystyle \alpha$ is :
Official answer
(2)
$\displaystyle 1.01$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.