Mathematics · 2025
JEE Main · 28 January 2025, Shift 1 · Q16
The sum of all local minimum values of the function f(x)= {1-2 x, x<-1; 1/3(7+2|x|), -1 ≤ x ≤ 2; 11/18(x-4)(x-5), x>2} is
The sum of all local minimum values of the function
$$f(x)=\left\{\begin{array}{lc}
1-2 x, & x<-1 \\
\frac{1}{3}(7+2|x|), & -1 \leq x \leq 2 \\
\frac{11}{18}(x-4)(x-5), & x>2
\end{array}\right.
$$
is
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \frac{157}{72}$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.