Mathematics · 2025
JEE Main · 29 January 2025, Shift 2 · Q18
Let f(x)=∫_0^x t ( t^2-9 t +20) dt, 1 ≤ x ≤ 5. If the range of f is [α, β], then 4(α+β) equals:
Let $\displaystyle f(x)=\int_0^x \mathrm{t}\left(\mathrm{t}^2-9 \mathrm{t}+20\right) \mathrm{dt}, 1 \leq x \leq 5$. If the range of $\displaystyle f$ is $\displaystyle [\alpha, \beta]$, then $\displaystyle 4(\alpha+\beta)$ equals :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 157$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.