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Mathematics · 2026

JEE Main · 2 April 2026, Shift 1 · Q18

The number of critical points of the function f(x)= {|(sin x)/x|, x ≠ 0; 1, x=0} in the interval (-2 π, 2 π) is equal to:

The number of critical points of the function $\displaystyle f(x)=\left\{\begin{array}{ll}\left|\frac{\sin x}{x}\right| & , x \neq 0 \\ 1 & , x=0\end{array}\right.$ in the interval $\displaystyle (-2 \pi, 2 \pi)$ is equal to :
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.