Mathematics · 2026
JEE Main · 4 April 2026, Shift 2 · Q12
max_0 ≤ x ≤ π(16 sin (x/2) cos^3(x/2)) is equal to:
$\displaystyle \max _{0 \leq x \leq \pi}\left(16 \sin \left(\frac{x}{2}\right) \cos ^3\left(\frac{x}{2}\right)\right)$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 3 \sqrt{3}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.