Mathematics · 2025
JEE Main · 4 April 2025, Shift 2 · Q17
Let a >0. If the function f(x)=6 x^3-45 a x^2+108 a^2 x+1 attains its local maximum and minimum values at the points x_1 and x_2 respectively such…
Let $\displaystyle \mathrm{a}>0$. If the function $\displaystyle f(x)=6 x^3-45 \mathrm{a} x^2+108 \mathrm{a}^2 x+1$ attains its local maximum and minimum values at the points $\displaystyle x_1$ and $\displaystyle x_2$ respectively such that $\displaystyle x_1 x_2=54$, then a $\displaystyle +x_1+x_2$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 18$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.