Mathematics · 2019
JEE Main · 11 January 2019, Shift 2 · Q77
The solution of the differential equation, (d y)/(d x)=(x-y)^2, when y(1)=1, is:
The solution of the differential equation,
$$\frac{\mathrm{d} y}{\mathrm{~d} x}=(x-y)^2, \text { when } y(1)=1, \text { is : }
$$
Official answer
(1)
$\displaystyle -\log _{\mathrm{e}}\left|\frac{1-x+y}{1+x-y}\right|=2(x-1)$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.