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Mathematics · 2022

JEE Main · 26 June 2022, Shift 1 · Q25

Let the solution curve y=y(x) of the differential equation (4+x^2) d y-2 x(x^2+3 y+4) d x=0 pass through the origin. Then y(2) is equal to \ \ \ \.

Let the solution curve $\displaystyle y=y(x)$ of the differential equation $\displaystyle \left(4+x^2\right) \mathrm{d} y-2 x\left(x^2+3 y+4\right) \mathrm{d} x=0$ pass through the origin. Then $\displaystyle y(2)$ is equal to \_\_\_\_.
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