If the solution of the differential equation (d y)/(d x)+e^x(x^2-2) y=(x^2-2 x)(x^2-2) e^2 x satisfies y(0)=0, then the value of y(2) is \ \ \ \

If the solution of the differential equation $\displaystyle \frac{d y}{d x}+e^x\left(x^2-2\right) y=\left(x^2-2 x\right)\left(x^2-2\right) e^{2 x}$ satisfies $\displaystyle y(0)=0$, then the value of $\displaystyle y(2)$ is \_\_\_\_