If y=y(x) is the solution of the differential equation (5+ e^x)/(2+y) · (d y)/(d x)+ e^x=0 satisfying y(0)=1, then a value of y( log_e 13) is:

If $\displaystyle y=y(x)$ is the solution of the differential equation $\displaystyle \frac{5+\mathrm{e}^x}{2+y} \cdot \frac{\mathrm{~d} y}{\mathrm{~d} x}+\mathrm{e}^x=0$ satisfying $\displaystyle y(0)=1$, then a value of $\displaystyle y\left(\log _{\mathrm{e}} 13\right)$ is :