Mathematics · 2020
JEE Main · 5 September 2020, Shift 2 · Q64
Let y=y(x) be the solution of the differential equation cos x (d y)/(d x)+2 y sin x= sin 2 x, x ∈(0, (π)/2). If y(π / 3)=0, then y(π / 4) is equal to:
Let $\displaystyle y=y(x)$ be the solution of the differential equation
$$\cos x \frac{d y}{d x}+2 y \sin x=\sin 2 x, x \in\left(0, \frac{\pi}{2}\right) .
$$
If $\displaystyle y(\pi / 3)=0$, then $\displaystyle y(\pi / 4)$ is equal to :
Official answer
(2)
$\displaystyle \sqrt{2}-2$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.