Mathematics · 2020
JEE Main · 4 September 2020, Shift 2 · Q58
Let f:(0, ∞) →(0, ∞) be a differentiable function such that f(1)= e and lim_t → x (t^2 f^2(x)-x^2 f^2( t ))/(t -x)=0. If f(x)=1, then x is equal to:
Let $\displaystyle f:(0, \infty) \rightarrow(0, \infty)$ be a differentiable function such that $\displaystyle f(1)=\mathrm{e}$ and
$$\lim _{\mathrm{t} \rightarrow x} \frac{\mathrm{t}^2 f^2(x)-x^2 f^2(\mathrm{t})}{\mathrm{t}-x}=0 .
$$
If $\displaystyle f(x)=1$, then $\displaystyle x$ is equal to:
Official answer
(2)
$\displaystyle \frac{1}{\mathrm{e}}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.