Mathematics · 2019
JEE Main · 11 January 2019, Shift 1 · Q77
If y(x) is the solution of the differential equation (d y)/(d x)+((2 x+1)/x) y=e^-2 x, x>0, where y(1)=1/2 e^-2, then:
If $\displaystyle y(x)$ is the solution of the differential
equation $\displaystyle \frac{d y}{d x}+\left(\frac{2 x+1}{x}\right) y=e^{-2 x}, x>0$,
where $\displaystyle y(1)=\frac{1}{2} e^{-2}$, then :
Official answer
(4)
$\displaystyle y(x)$ is decreasing in $\displaystyle \left(\frac{1}{2}, 1\right)$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.