Mathematics · 2024
JEE Main · 9 April 2024, Shift 1 · Q16
The shortest distance between the lines (x-3)/4=(y+7)/-11=(z-1)/5 and (x-5)/3=(y-9)/-6=(z+2)/1 is:
The shortest distance between the lines $\displaystyle \frac{x-3}{4}=\frac{y+7}{-11}=\frac{z-1}{5}$ and $\displaystyle \frac{x-5}{3}=\frac{y-9}{-6}=\frac{z+2}{1}$ is:
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \frac{187}{\sqrt{563}}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.