Mathematics · 2025
JEE Main · 22 January 2025, Shift 2 · Q14
The perpendicular distance, of the line (x-1)/2=(y+2)/-1=(z+3)/2 from the point P (2,-10,1), is:
The perpendicular distance, of the line $\displaystyle \frac{x-1}{2}=\frac{y+2}{-1}=\frac{z+3}{2}$ from the point $\displaystyle \mathrm{P}(2,-10,1)$, is :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 3 \sqrt{5}$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.