Mathematics · 2025
JEE Main · 23 January 2025, Shift 1 · Q15
Let P be the foot of the perpendicular from the point Q (10,-3,-1) on the line (x -3)/7=(y -2)/-1=(z +1)/-2. Then the area of the right angled…
Let P be the foot of the perpendicular from the point $\displaystyle \mathrm{Q}(10,-3,-1)$ on the line $\displaystyle \frac{\mathrm{x}-3}{7}=\frac{\mathrm{y}-2}{-1}=\frac{\mathrm{z}+1}{-2}$. Then the area of the right angled triangle PQR , where R is the point $\displaystyle (3,-2,1)$, is
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 3 \sqrt{30}$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.