Mathematics · 2013
JEE Main · 22 April 2013, Shift 1 · Q83
The number of solutions of the equation, sin^-1 x=2 tan^-1 x (in principal values) is:
The number of solutions of the equation, $\displaystyle \sin ^{-1} x=2 \tan ^{-1} x$ (in principal values) is :
Official answer
(4)
$\displaystyle 3$
More from Inverse Trigonometric Functions
- If α= cos^-1(3/5), β= tan^-1(1/3), where 0<α, β<(π)/2, then α-β is equal to:2019
- Let [x] denote the greatest integer less than or equal to x. Then the domain of f(x)= sec^-1(2[x]+1) is:2025
- Let x= sin (2 tan^-1 α) and y= sin (1/2 tan^-1 4/3). If S={α ∈ R: y^2=1-x}, then Σ_α ∈ S 16 α^3 is equal to \ \ \ \.2022
- All x satisfying the inequality ( cot^-1 x)^2-7( cot^-1 x)+10>0, lie in the interval:2019
- The value of tan^-1((cos ((15 π)/4)-1)/(sin ((π)/4))) is equal to:2022
- If (π)/4+Σ_p=1^11 tan^-1((2^p-1)/(1+2^2 p-1))=α, then tan α is equal to ____.2026
- tan (2 tan^-1 1/5+ sec^-1 (√5)/2+2 tan^-1 1/8) is equal to:2022
- If the domain of the function f(x)=(cos^-1 √(x^2-x+1))/(√(sin^-1((2 x-1)/2))) is the interval (α, β], then α+β is equal to:2021
JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.