Mathematics · 2019
JEE Main · 8 April 2019, Shift 1 · Q89
If α= cos^-1(3/5), β= tan^-1(1/3), where 0<α, β<(π)/2, then α-β is equal to:
If $\displaystyle \alpha=\cos ^{-1}\left(\frac{3}{5}\right), \beta=\tan ^{-1}\left(\frac{1}{3}\right)$, where
$\displaystyle 0<\alpha, \beta<\frac{\pi}{2}$, then $\displaystyle \alpha-\beta$ is equal to:
Official answer
(2)
$\displaystyle \sin ^{-1}\left(\frac{9}{5 \sqrt{10}}\right)$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.