Mathematics · 2022
JEE Main · 26 June 2022, Shift 2 · Q12
The locus of the mid point of the line segment joining the point (4,3) and the points on the ellipse x^2+2 y^2=4 is an ellipse with eccentricity:
The locus of the mid point of the line segment joining the point $\displaystyle (4,3)$ and the points on the ellipse $\displaystyle x^2+2 y^2=4$ is an ellipse with eccentricity:
Official answer
(3)
$\displaystyle \frac{1}{\sqrt{2}}$
More from Ellipse
- Let the line y-x=1 intersect the ellipse x^2/2+y^2/1=1 at the points A and B. Then the angle made by the line segment AB at the center of the ellipse…2026
- If α x+β y=109 is the equation of the chord of the ellipse x^2/9+y^2/4=1, whose mid point is (5/2, 1/2), then α+β is equal to:2025
- Let an ellipse with centre (1,0) and latus rectum of length 1/2 have its major axis along x -axis. If its minor axis subtends an angle 60^° at the…2023
- Let L be a common tangent line to the curves 4 x^2+9 y^2=36 and (2 x)^2+(2 y)^2=31. Then the square of the slope of the line L is \ \ \ \.2021
- Let (h, k) lie on the circle C: x^2+y^2=4 and the point (2 h+1,3 k+2) lie on an ellipse with eccentricity e. Then the value of 5/e^2 is equal to ____.2026
- The equation of the chord, of the ellipse x^2/25+y^2/16=1, whose mid-point is (3,1) is:2025
- The locus of mid-points of the line segments joining (-3, -5) and the points on the ellipse x^2/4+y^2/9=1 is:2021
- The length of the latus-rectum of the ellipse, whose foci are (2,5) and (2,-3) and eccentricity is 4/5, is2025
JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.