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Mathematics · 2025

JEE Main · 29 January 2025, Shift 2 · Q12

If α x+β y=109 is the equation of the chord of the ellipse x^2/9+y^2/4=1, whose mid point is (5/2, 1/2), then α+β is equal to:

If $\displaystyle \alpha x+\beta y=109$ is the equation of the chord of the ellipse $\displaystyle \frac{x^2}{9}+\frac{y^2}{4}=1$, whose mid point is $\displaystyle \left(\frac{5}{2}, \frac{1}{2}\right)$, then $\displaystyle \alpha+\beta$ is equal to :
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.