Mathematics · 2025
JEE Main · 24 January 2025, Shift 2 · Q13
The equation of the chord, of the ellipse x^2/25+y^2/16=1, whose mid-point is (3,1) is:
The equation of the chord, of the ellipse $\displaystyle \frac{x^2}{25}+\frac{y^2}{16}=1$, whose mid-point is $\displaystyle (3,1)$ is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 48 x+25 y=169$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.