Mathematics · 2026
JEE Main · 23 January 2026, Shift 1 · Q12
Let the line y-x=1 intersect the ellipse x^2/2+y^2/1=1 at the points A and B. Then the angle made by the line segment AB at the center of the ellipse…
Let the line $\displaystyle y-x=1$ intersect the ellipse $\displaystyle \frac{x^2}{2}+\frac{y^2}{1}=1$ at the points A and B. Then the angle made by the line segment AB at the center of the ellipse is :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \frac{\pi}{2}+\tan ^{-1}\left(\frac{1}{4}\right)$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.