Mathematics · 2025
JEE Main · 28 January 2025, Shift 2 · Q11
If the midpoint of a chord of the ellipse x^2/9+y^2/4=1 is (√ 2, 4 / 3), and the length of the chord is (2 √ α)/3, then α is:
If the midpoint of a chord of the ellipse $\displaystyle \frac{x^2}{9}+\frac{y^2}{4}=1$ is $\displaystyle (\sqrt{2}, 4 / 3)$, and the length of the chord is $\displaystyle \frac{2 \sqrt{\alpha}}{3}$, then $\displaystyle \alpha$ is :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 22$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.