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Mathematics · 2014
JEE Main 2014 · 2014-04-06 Offline · Q80
The locus of the foot of perpendicular drawn from the centre of the ellipse x^2+3 y^2=6 on any tangent to it is:
The locus of the foot of perpendicular drawn from the centre of the ellipse $\displaystyle x^2+3 y^2=6$ on any tangent to it is :
Official answer
(1)
$\displaystyle \left(x^2+y^2\right)^2=6 x^2+2 y^2$
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.