Mathematics · 2019
JEE Main · 10 January 2019, Shift 2 · Q81
Let S ={(x, y) ∈ R^2: y^2/(1+ r)-x^2/(1- r)=1}, where r ≠ ± 1. Then S represents:
Let
$$\mathrm{S}=\left\{(x, y) \in \mathrm{R}^2: \frac{y^2}{1+\mathrm{r}}-\frac{x^2}{1-\mathrm{r}}=1\right\},
$$
where $\displaystyle \mathbf{r} \neq \pm 1$. Then S represents :
Official answer
(1)
an ellipse whose eccentricity is $\displaystyle \sqrt{\frac{2}{\mathrm{r}+1}}$, when $\displaystyle \mathrm{r}>1$.
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.