The lines (x-2)/2=y/-2=(z-7)/16 and (x+3)/4=(y+2)/3=(z+2)/1 intersect at the point P. If the distance of P from the line (x+1)/2=(y-1)/3=(z-1)/1 is…

The lines $\displaystyle \frac{x-2}{2}=\frac{y}{-2}=\frac{z-7}{16}$ and $\displaystyle \frac{x+3}{4}=\frac{y+2}{3}=\frac{z+2}{1}$ intersect at the point P. If the distance of P from the line $\displaystyle \frac{x+1}{2}=\frac{y-1}{3}=\frac{z-1}{1}$ is $\displaystyle l$, then $\displaystyle 14 l^2$ is equal to $\displaystyle \_\_\_\_$.