Mathematics · 2019
JEE Main · 12 April 2019, Shift 2 · Q77
The general solution of the differential equation (y^2-x^3) d x-x y d y=0(x ≠ 0) is: (where c is a constant of integration)
The general solution of the differential equation $\displaystyle \left(y^2-x^3\right) \mathrm{d} x-x y \mathrm{~d} y=0(x \neq 0)$ is : (where $\displaystyle c$ is a constant of integration)
Official answer
(3)
$\displaystyle y^2+2 x^3+c x^2=0$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.