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Mathematics · 2020
JEE Main · 7 January 2020, Shift 1 · Q62
If y=y(x) is the solution of the differential equation, e^y((d y)/(d x)-1)= e^x such that y(0)=0, then y(1) is equal to:
If $\displaystyle y=y(x)$ is the solution of the differential equation, $\displaystyle \mathrm{e}^y\left(\frac{\mathrm{~d} y}{\mathrm{~d} x}-1\right)=\mathrm{e}^x$ such that $\displaystyle y(0)=0$, then $\displaystyle y(1)$ is equal to :
Official answer
(1)
$\displaystyle 1+\log _{\mathrm{e}} 2$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.