Mathematics · 2020
JEE Main · 7 January 2020, Shift 2 · Q63
Let y=y(x) be the solution curve of the differential equation, (y^2-x) (d y)/(d x)=1, satisfying y(0)=1. This curve intersects the x -axis at a point…
Let $\displaystyle y=y(x)$ be the solution curve of the differential equation, $\displaystyle \left(y^2-x\right) \frac{\mathrm{d} y}{\mathrm{~d} x}=1$, satisfying $\displaystyle y(0)=1$. This curve intersects the $\displaystyle x$-axis at a point whose abscissa is :
Official answer
(1)
$\displaystyle 2-\mathrm{e}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.