Mathematics · 2013
JEE Main · 9 April 2013, Shift 1 · Q90
Let f(x)=(x^2-x)/(x^2+2 x), x ≠ 0,-2. Then d/(d x)[f^-1(x)] (wherever it is defined) is equal to:
Let $\displaystyle f(x)=\frac{x^2-x}{x^2+2 x}, x \neq 0,-2$. Then $\displaystyle \frac{d}{d x}\left[f^{-1}(x)\right]$ (wherever it is defined) is equal to :
Official answer
(2)
$\displaystyle \frac{3}{(1-x)^2}$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.