Mathematics · 2018
JEE Main · 15 April 2018, Shift 2 · Q72
If f(x)= sin^-1((2 × 3^x)/(1+9^x)), then f^′(-1/2) equals:
If $\displaystyle f(x)=\sin ^{-1}\left(\frac{2 \times 3^x}{1+9^x}\right)$, then $\displaystyle f^{\prime}\left(-\frac{1}{2}\right)$ equals :
Official answer
(2)
$\displaystyle \sqrt{3} \log _{\mathrm{e}} \sqrt{3}$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.