For the curve C:(x^2+y^2-3)+(x^2-y^2-1)^5=0, the value of 3 y^′-y^3 y^′ ′, at the point (α, α), α>0, on C, is equal to \ \ \ \.

For the curve $\displaystyle \mathrm{C}:\left(x^2+y^2-3\right)+\left(x^2-y^2-1\right)^5=0$, the value of $\displaystyle 3 y^{\prime}-y^3 y^{\prime \prime}$, at the point $\displaystyle (\alpha, \alpha)$, $\displaystyle \alpha>0$, on C, is equal to \_\_\_\_.