Mathematics · 2023
JEE Main · 1 February 2023, Shift 2 · Q68
If y(x)=x^x, x>0, then y^′ ′(2)-2 y^′(2) is equal to:
If $\displaystyle y(x)=x^x, x>0$, then $\displaystyle y^{\prime \prime}(2)-2 y^{\prime}(2)$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 4\left(\log _{\mathrm{e}} 2\right)^2-2$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.