Mathematics · 2026
JEE Main · 4 April 2026, Shift 1 · Q17
Let f be a real polynomial of degree n such that f(x)=f^′(x) f^′ ′(x), for all x ∈ R. If f(0)=0, then 36(f^′(2)+f^′ ′(2)+∫_0^2 f(x) d x) is equal to:
Let $\displaystyle f$ be a real polynomial of degree $\displaystyle n$ such that $\displaystyle f(x)=f^{\prime}(x) f^{\prime \prime}(x)$, for all $\displaystyle x \in \mathbb{R}$. If $\displaystyle f(0)=0$, then $\displaystyle 36\left(f^{\prime}(2)+f^{\prime \prime}(2)+\int_0^2 f(x) d x\right)$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 56$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.