Mathematics · 2023
JEE Main · 25 January 2023, Shift 1 · Q68
Let y (x)=(1+x)(1+x^2)(1+x^4)(1+x^8)(1+x^16). Then y^′- y^′ ′ at x=-1 is equal to:
Let $\displaystyle \mathrm{y}(x)=(1+x)\left(1+x^2\right)\left(1+x^4\right)\left(1+x^8\right)\left(1+x^{16}\right)$. Then $\displaystyle \mathrm{y}^{\prime}-\mathrm{y}^{\prime \prime}$ at $\displaystyle x=-1$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 496$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.