Mathematics · 2018
JEE Main · 15 April 2018, Shift 1 · Q71
If x^2+y^2+ sin y=4, then the value of (d^2 y)/(d x^2) at the point (-2, 0) is:
If $\displaystyle x^2+y^2+\sin y=4$, then the value of $\displaystyle \frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}$ at the point $\displaystyle (-2, 0)$ is :
Official answer
(1)
$\displaystyle -34$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.