Mathematics · 2025
JEE Main · 22 January 2025, Shift 2 · Q17
Let f(x)=∫_0^x^2 (t^2-8 t +15)/(e^t) dt, x ∈ R. Then the numbers of local maximum and local minimum points of f, respectively, are:
Let $\displaystyle f(x)=\int_0^{x^2} \frac{\mathrm{t}^2-8 \mathrm{t}+15}{\mathrm{e}^{\mathrm{t}}} \mathrm{dt}, x \in \mathbf{R}$. Then the numbers of local maximum and local minimum points of $\displaystyle f$, respectively, are :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 2$ and $\displaystyle 3$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.