Mathematics · 2021
JEE Main · 26 August 2021, Shift 1 · Q68
Let f(x)= cos (2 tan^-1 sin ( cot^-1 √((1-x)/x))), 0<x<1. Then:
Let $\displaystyle f(x)=\cos \left(2 \tan ^{-1} \sin \left(\cot ^{-1} \sqrt{\frac{1-x}{x}}\right)\right), 0<x<1$. Then :
Official answer
(3)
$\displaystyle (1-x)^2 f^{\prime}(x)+2(f(x))^2=0$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.