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Mathematics · 2021

JEE Main · 26 August 2021, Shift 2 · Q77

If Σ_r =1^50 tan^-1 1/(2 r^2)= p, then the value of tan p is:

If $\displaystyle \sum_{\mathrm{r}=1}^{50} \tan ^{-1} \frac{1}{2 \mathrm{r}^2}=\mathrm{p}$, then the value of $\displaystyle \tan \mathrm{p}$ is :
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.