Let the values of λ for which the shortest distance between the lines (x-1)/2=(y-2)/3=(z-3)/4 and (x-λ)/3=(y-4)/4=(z-5)/5 is 1/(√ 6) be λ_1 and λ_2.…

Let the values of $\displaystyle \lambda$ for which the shortest distance between the lines $\displaystyle \frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$ and $\displaystyle \frac{x-\lambda}{3}=\frac{y-4}{4}=\frac{z-5}{5}$ is $\displaystyle \frac{1}{\sqrt{6}}$ be $\displaystyle \lambda_1$ and $\displaystyle \lambda_2$. Then the radius of the circle passing through the points $\displaystyle (0,0),\left(\lambda_1, \lambda_2\right)$ and $\displaystyle \left(\lambda_2, \lambda_1\right)$ is